Question

in the given figure AD parallel BC and angle BAC = 40 degree what is the measure of angle DBC ​

Answer 1

∠DBC = 40°  if ∠BCA  = 40°

Step-by-step explanation:

in the given figure AD parallel BC

AD ║ BC

& AC intersect it

=> ∠DAC = ∠BCA

As per diagram ∠BCA  = 40°

=> ∠DAC = 40°

∠DBC = ∠DAC  ( angle subtended by chord CD  in same arc segment)

=> ∠DBC = 40°

∠DBC = 40°  if ∠BCA  = 40°

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Answer 2

Answer:

angle DBC =40°

Step-by-step explanation:

AD||BC

Angle BCA = 40° given

angle BCA = angle DAC ( alt.int.angle)

hence, BCA=DAC= 40°

angle DAC = angle DBC ( angle subtended by same segment is equal)

DAC = DBC = 40°

HENCE, DBC = 40°