In The Given Figure, AD Perpendicular CD and BC Perpendicular CD.If AQ=Bp And DP =CQ , Prove That angle DAQ = Angle CBP
And Please Ignore These Lines Between P And Q
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here it is...
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in ∆ADQ and ∆BCP
angle ADQ = angle BCP =90°
AQ. = BP
DP = CQ. (
∆ADQ congruent ∆BCP
angle DAQ = angle CBP
angle ADQ = angle BCP =90°
AQ. = BP
DP = CQ. (
∆ADQ congruent ∆BCP
angle DAQ = angle CBP
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