Math, asked by kuldeepkumar345876, 6 months ago

In the given figure, ∆ADB =~ ∆CDB. Find the values of x and y.​

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Answers

Answered by ranjitasingh2005
3

Answer:

<ADB=<CDB

y+5=48

y=48-5

y=43°

<ABD=<CBD

3x+5=44

3x=44-5

3x=39

x=13

Step-by-step explanation:

asΔADB=~ΔCDB

<ADB=<CDB(cpct)

<ABD=<CBD(cpct)

Answered by kadampoonamoct10
4

Answer:

∆ADBis congruent with∆CDB.......(Given)

now,

angle D =~ angle D.......(common angle)

y+5°=48°

y=48-5

y=43

now,

angleB=~angle B.......(common angle)

44°=3x+5°

44-5=3x

39=3x

39/3=x

x=13.

VALUE OF x=13 & y=43.

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