Question

In the given figure AE=AC& DE=AB find Angle CAE


Pls find the image

Answer 1

$\huge\mathcal\pink{ANSWER:-}$

Given :- In fig :

AC = AE, AB= AD

& angle BAD = angle EAC

To prove :- BC = DE

Proof :- angle 1 = angle 2 (given)

Add angle 3 on both the sides

--> angle 1 + angle 3 = angle 2 + angle 3

or , angle BAC = angle DAC --------1.

Now , In triangle ABC and driangle ADE

angle BAC = angle DAE ( from 1.)

AB = AD (given)

AC = AE (given)

Therefore , triangle ABC congruent to triangle ADE (SAS).

Therefore, BC = DE (cpct)

Answer 2

Answer:

Given :- In fig :

AC = AE, AB= AD

& angle BAD = angle EAC

To prove :- BC = DE

Proof :- angle 1 = angle 2 (given)

Add angle 3 on both the sides

--> angle 1 + angle 3 = angle 2 + angle 3

or , angle BAC = angle DAC --------1.

Now , In triangle ABC and driangle ADE

angle BAC = angle DAE ( from 1.)

AB = AD (given)

AC = AE (given)

Therefore , triangle ABC congruent to triangle ADE (SAS).

Therefore, BC = DE (cpct)