In the given figure, AE = DE, CE = BE then prove that AB = CD.
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given,
AE=DE &CE =BE
PROOF:-
In ∆ABE &∆ECD
AE=DE (given)
CE=BE (given)
<AEB =<DEC (vertically opposite angles)
therefore ∆AEB IS CONGRUENT TO ∆ECD
hence AB =CD (C.P.C.T)
AE=DE &CE =BE
PROOF:-
In ∆ABE &∆ECD
AE=DE (given)
CE=BE (given)
<AEB =<DEC (vertically opposite angles)
therefore ∆AEB IS CONGRUENT TO ∆ECD
hence AB =CD (C.P.C.T)
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