In the given figure, ΔAHK is similar to ΔABC. If AK = 10 cm, BC = 3.5 cm and HK = 7 cm, find AC
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from triangle ABC&AHK
angle CAB=angle HAK
Ais mid point so AB=AH
&CA=AK
CB=HK
triangle ABC is congruent to AHK
AC=AK
AC=10
angle CAB=angle HAK
Ais mid point so AB=AH
&CA=AK
CB=HK
triangle ABC is congruent to AHK
AC=AK
AC=10
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