in the given figure, all the adjacent sides are at right angles .find (1)perimeter of the figure (2) area of the figure
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1) perimeter = sum of all sides
= 10 + 12 + 4 + 8 + 4
= 28 cm
2) area of figure is above in the pic
= 10 + 12 + 4 + 8 + 4
= 28 cm
2) area of figure is above in the pic
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Perimeter =sum of the sides
=4+10+12+4+8
=38 cm
Area =(First make it into two rectangles by drawing one line and a square by drawing one more line)
Area of rectangle 1 = 4×6=24 cm^2
Area of rectangle 2= 4×8=32 cm^2
Area the square formed = 4^2=16 cm^2
So,area of the total figure = 24+32+16=72 cm^2
=4+10+12+4+8
=38 cm
Area =(First make it into two rectangles by drawing one line and a square by drawing one more line)
Area of rectangle 1 = 4×6=24 cm^2
Area of rectangle 2= 4×8=32 cm^2
Area the square formed = 4^2=16 cm^2
So,area of the total figure = 24+32+16=72 cm^2
Shashank8th:
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