Math, asked by GovindKrishnan, 1 year ago

In the given figure, all the sides of the quadrilateral ABCD touch a circle with centre O. Prove that ∠AOB + ∠COD = 180° and ∠BOC + ∠AOD = 180°.

Answer with complete steps & explanations.

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Answered by maria9

the answer is the attachment

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GovindKrishnan: Thanks! ♥

Ankit1234: Amazing

maria9: thank u govind :)

maria9: thanks Ankit :)

Answered by mysticd

I hope this helps you.

: )

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GovindKrishnan: Thanks Sir! ♥

mysticd: : )

maria9: nyc answer sir :)

mysticd: : )

Ankit1234: By the way there was no need to prove congruent in both the answers. Since the teo tangents drawn from an external points subtent equal angles at the centre.

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In the given figure, all the sides of the quadrilateral ABCD touch a circle with centre O. Prove that ∠AOB + ∠COD = 180° and ∠BOC + ∠AOD = 180°. Answer with complete steps & explanations.

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In the given figure, all the sides of the quadrilateral ABCD touch a circle with centre O. Prove that ∠AOB + ∠COD = 180° and ∠BOC + ∠AOD = 180°.

Answer with complete steps & explanations.