In the given figure alongside, angle ABC : angle BAC=2:3 and angle ACD=130^ find the value of angle ABC , angle BAC and angle ACB
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Let angle ABC, BAC AND ACB be = x,y and z
Step-by-step explanation:
Let the ratio be 2a and 3a.
2a+3a=130° (exterior angle=sum of two opposite interior angles)
5a=130°
a=26°
x=2a =2*26°=52°
y=3a=3*26°=78°
z+130°=180°(angles on a straight line)
z=180°-130°
z=50°
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