in the given figure, alongside PSR,RTQ and PAQ are three semicircles of diameters 10cm , 3cm n 7cm respectively. find the perimeter of the shaded region.....
[CBSE 2014]
Answers
Answer:
22 square centimetre
Step-by-step explanation:
ar(PSR)=πr^2
=22/7×5
=110/7square centimetre
=15.71(approx.)square centimetre
ar(PAQ)=πr^2
=22/7×3.5
=11 square centimetre
ar(QRT)=πr^2
=22/7×3/2
=33/7square centimetre
=4.71(approx.)square centimetre
area of shaded region=ar(PSR+QTR-PAQ)
=110/7+11-33/7
=187/7-33/7
=154/7
=22square centimetre
Answer:
Hey mate, here is your answer
Step - by - step explanation :
22 centimetres
Radius of semicircle PSR = 10cm/2 = 5cm
Radius of semicircle PAQ = 7cm/2 = 3.5cm
Radius of semicircle RTQ = 3cm/2 = 1.5cm
Perimeter of shaded region = perimeter of semicircle PSR + perimeter of semicircle RTQ + perimeter of semicircle PAQ
And we know that perimeter of a semicircle = \pi * rπ∗r
Required perimeter = \pi * 5 cm + \pi *1.5 cm + \pi * 3.5 cmπ∗5cm+π∗1.5cm+π∗3.5cm
= 3.14 (5cm + 1.5cm +3.5 cm) = 3.14 x 10cm = 31.4 cm=3.14(5cm+1.5cm+3.5cm)=3.14x10cm=31.4cm
Thank you
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