Question

in the given figure am perpendicular and an is the bisector ​

Answer 1

Step-by-step explanation:

Since, in ΔABC:

∠A+∠B+∠C=180°

⟹∠A=180°−55°−65°=60°.

Now, AN is angle bisector of ∠A then,

∠CAN=∠BAN=30°

Now, ∠ANM=∠NCA+∠CAN=55°+30°=85°........(Sum of two interior angles is equal to opposite exterior angle).

Now, in ΔANM:

∠AMN=90° and

∠MAN+∠ANM+∠AMN=180°

⟹∠MAN=180°−90°−85°=5°