Question

In the given figure, an equilateral triangle ABC is inscribed in a circle with centre O. Find ∠BOC == ________. ​

Answer 1

option B is the correct answer 120

solution

We have,

ΔABC is an equilateral triangle

Since, each angle is 60

o

.

Now, using property Angle subtend at the centre of circle is double angle at any point on circumference of circle

∠BOC=2∠BAC

∠BOC=2×60

o

∠BOC=120

o

Hence, this is the answer.

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