in the given figure, an ideal pendulum oscillates in a vacuum between two extreme points A and B if it goes from position a to position b and then Returns from position b to the mean position see in 3 seconds then what time it will complete 3. 5 oscillations.
Answers
The answer will be 14 seconds.
Explanation:
An ideal pendulum is given to be oscillating in a vacuum, which means there will be no air drag opposing the motion of the pendulum which reduces its speed and amplitude. Therefore, the distance AC and BC will be constant.
Now, let us assume 1 round to be between points A and C,and points B and C. So, as given, it take 3 seconds to complete 3 rounds from A to C, then to B and then back to C.
So if we divide 3 rounds by 3 seconds, then it comes to be 1, i.e. it takes 1 second for the pendulum to complete one round. So in 3.5 oscillations there will be 14 rounds as 1 oscillation consists of 4 rounds.
Therefore, total time taken for the pendulum to complete 14 rounds will be
= 14 * time to complete one round
= 14*1
= 14 seconds
Answer:
Travelling time from A to B to C is 3 second.
For one complete oscillations A to B to A.
We know system is in vacuum,
Hence, time taken B to C will be equal to C to A.
For .75 oscillations time is 3 second
Hence for 1 oscillations time will be sec.
So, for 3.5 oscillations time will be
= 14 secs
Explanation is done