Question

In the given figure an isosceles triangle ABC, witg AB=AC, circumscribes a circle.Prove that the point of contact P bisects the base BC.

Answer 1

AR =AQ
BR=BP. These all are tangents
CP=CQ

Now AB = AC.
=>. AB - AR = AC - AR
=>. AB - AR = AC - AQ ( AR = AQ )
=>. BR = CQ
=>. BP = CE ( BR = BP and
CQ = CE )