IN the given figure AND is a right triangle and right angled at B such that angleBCA=angleBAC show that hypotenuse AC=2BC
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In Δ ABC
given angle BCA= angle BAC
So the side AB=BC
D is point on BC
using Pythagoras theorem
AC²=AB²+BC²
AC²=2BC²
adding square at both side
we get, √AC²=√2BC²
that is AC=2BC
I hope this will help you mark me brainliest
given angle BCA= angle BAC
So the side AB=BC
D is point on BC
using Pythagoras theorem
AC²=AB²+BC²
AC²=2BC²
adding square at both side
we get, √AC²=√2BC²
that is AC=2BC
I hope this will help you mark me brainliest
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