Question

In the given figure, angle 1 = angle 2 and AB = AC. Prove that
(i) angle B = angle C
(ii) BD = DC
(iii) AD is perpendicular to BC
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Answer 1

Answer:

AD is perpendicular to BC

Step-by-step explanation:

In ∆ ADB and ∆ADC

It is given that

AB = AC and angle 1 = angle 2

AD = AD is common

Hence, ∆ ADB =~ ∆ ADC (SAS Axiom)

(i) Angle B = Angle C (by c.p.c.t)

(ii) Angle BD= Angle DC (by c.p.c.t)

(iii) Angle ADB = Angle ADC = 180° is a linear pair

We know that,

Angle ADB +Angle ADC= 180° is a linear pair

So we get,

Angle ADB= Angle = 90°

Hence, AD is perpendicular to BC

Therefore it is prove

Answer 2

Answer:

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