in the given figure angle 1 = angle 2prove
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angle A = angle A(Ad perpendicular to D)
ab= ac(given)
ad = ad (common)
∆ABD =~ ∆ADC by (SAS) side angle side
angle B = angle C by ( cpct ) corresponding parts of congrance triangle
ab= ac(given)
ad = ad (common)
∆ABD =~ ∆ADC by (SAS) side angle side
angle B = angle C by ( cpct ) corresponding parts of congrance triangle
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