Question

in the given figure, angle a>angle b,show that angle ATM<angle AMT​

Answer 1

Step-by-step explanation:

Answer in attachment...................

• A+

Answer 2

∠ATM  < ∠AMT

Step-by-step explanation:

∠a  = ∠AMT  + ∠A

(Exterior angle of Triangle = Sum of opposite interior angle)

∠b  = ∠ATM  + ∠A

(Exterior angle of Triangle = Sum of opposite interior angle)

∠a > ∠b   given

=> ∠AMT  + ∠A  > ∠ATM  + ∠A

Subtracting ∠A from both sides

=> ∠AMT > ∠ATM

=> ∠ATM  < ∠AMT

QED

Hence proved

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