In the given figure, angle ABC=90° and P is the mid-point of AC. Find the length of AP
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Ac^2=9+16. AC=√25=5. AP=2.5
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AB^2 + BC^2 = AC^2
3^2 + 4^2 = ( AP * 2 )^2
25^1÷2 = 2 AP
AP = 5 ÷ 2
AP = 2.5
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