In the given figure, angle ABC = angle DCB = 90°,
AB = 6, DC = 8, then A( ∆ABC)/A(DCB)=?
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∆ABC and ∆DCB have same base BC. ∴ A(∆ABC)/A(∆DCB) = AB/DC [Triangles having equal base] = 6/8 ∴ A(∆ABC)/A(DCB) = 3/4Read more on Sarthaks.com - https://www.sarthaks.com/850384/in-the-adjoining-figure-abc-dcb-90-ab-6-dc-8-then-a-abc-a-dcb
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