in the given figure angle abc is an equilateral triangle here BD and CE are marion's show that BD is equal to CE
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Given: ABC is an equilateral triangle.
BD and CE are two medians of the equilateral triangle ABC.
To Find: BD = CD
Solution: ABC is an equilateral triangle.
So AB = BC = AC
Let us consider that, AB = BC = AC = x
As BD and CE are medians to the triangle, then
⇒AD = CD, AE = BE
Now, In triangles BDC and BCE we have,
BC ( Common Side )
CD = BE ( As AC = AB )
And 1/2AB = 1/2 AC ( As ABC is an equilateral triangle )
So by the SAS congruence criterion, we get that
Triangle BDC ≅ Triangle BCE
⇒ BD = CE ( Proved )
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