in the given figure angle ABC is equal to 60 degree ,Angle BCE is equal to 25 degree ,Angle DCE is equal to 35 degree and Angle CEF is equal to 145 degree then find the relation between AB and EF.
(note:can check the diagram photo)
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Answer:
AB parallel to EF
Step-by-step explanation:
So, in lines AB , CD ∠ABC = 60.
Also, ∠BCD = ∠DCE + ∠BCE.
=> ∠BCD = 35 + 25 = 60
So, ∠ABC = ∠ BCD = 60.
Now, if you observe carefully, you see that ∠ABC and ∠BCD are alternate interior angles. Also, they both are same. So, you can say that line AB is parallel to line CD because the alternate interior angles are equal.
=> AB ∥ CD ( keep it as equation one. )
Now in lines EF and CD,
∠FEC , ∠EFC are co-interior angles. So, if their sum is 180, you can conclude that EF ∥ CD. Here, 145 + 35 = 180.
So, EF ∥ CD ( equation two )
From equation 1 and 2,
you can say AB ∥ EF ∥ CD. So, AB ∥ EF
Mark as brainliest please. Hope you understood.
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