Question

in the given figure angle ABE=139 degree and angle ACD=156degree .Find angle BAC. (correct answer is 115 but i need with solution so plz help me)​

Answer 1

Answer:

Angle EBA=139

Angle DCA=156

Angle EBA+angle ABC =180      linear pair

139+angle ABC =180  

angle ABC = 41

Angle ACB+angle ACD =180                    linear pair

Angle ACB+156=180

Angle ACB= 24

41+24+ angle a=180

65+ angle a=180

angle a= 115

Answer 2

Answer:

you answer is 115

so solution is

Angle ABE = 139

Angle ACD =156

so angle B is 180°

and angle C is also 180°

angle B - angle 139°

= 41° we say angle B

and angle C - angle 156°

= 65° we say angle C

,

So triangle has three angle = 180°

angle B + angle C + x = 180°

41° + 65° + x = 180°

65° + x = 180°

x = 180° - 65°

x = 115°

ANSWER IS 115 °

HOPE IS HEIPFUL FOR YOU

ANNU SHARMA