Question

In the giveñ figure, angle AOB is a straight angle. If TOB = (5x)° and
TOA=(x +30) °, find the value of x.​

Answer 1

Answer:

Solution 10:

∠AOP = x + 30°

∠BOP = x- 30°

But, ∠AOP + ∠BOP = 180°

> x + 30° + x - 30° = 180°

> 2x = 180°

> x = 90°

(i) ∠AOP = x + 30° = 90° + 30° = 120°

(ii) ∠BOP = x - 30° = 90° - 30° = 60°

(iii) ∠AOP is an obtuse angle

(iv) ∠BOP is an acute angle

Answer 2

Answer:

Angle TOB + Angle TOB = Angle AOB

(5x)° + (x+30)° = 180°

(6x)° + 30° = 180°

x = 150/6

x = 25

Hope It Helped...