Question

in the given figure , angle B = 65 degree and angle C =45 degree in triangle ABC and DAE and BC parallel lines if angle DAB = x degree and angle EAC = y degree , find the value of x and y.​

Answer 1

Answer:

X = 65 Y=45

Step-by-step explanation:

if line DE and line BC are parallel we can take line BA as their transversal.

so angle Dab will be equal to angle ABC by alternate interio angle ppty which is 65

so X=65

if we take line CA as the transversal angle acb will be equal to angle cae by alternate interior angle ppty which is 45

so y =45

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Answer 2

Answer:

✧✧Required Answer:✧✧

$= > x = {65}^{o} \\ = > y = {45}^{o}$

✧✧Given:✧✧

• angle B = 65 degree and angle C =45 degree in triangle ABC and DAE and BC parallel lines if angle DAB = x degree and angle EAC = y degree

✧✧To Find:✧✧

• find the value of x and y.

✧✧Solution✧✧

$Form \: the \: question, \: we \: have,  \\ </p><p></p><p>∠B=65 {}^{o} ,∠C=45 {}^{o} , DAE∥BC \\ </p><p></p><p>$

$The \: given \: lines \: are \: parallel,  \\ </p><p></p><p>∠B=x {}^{o} =65 {}^{o} </p><p></p><p>$

$∵Alternate angles when AB is take as the transversal line \)$

$∠C=y {}^{o} =45 {}^{o}$

$[ ∵ Alternate angles when AB is taken as the transversal line]  \)$