in the given figure angle b is equal to 70 degree and CE parallel to AB if angle a ECD is equal to 35 degree find values of X Y and Z
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AB || CE and BC is transversal
then, angle B = y = 70° ( alternate interior angle)
now ,
angle BCA + angle BCE + angle ECD = 180°
( as ACD is a straight line )
z°+y°+35° = 180°
z° +70°+35° = 180°
z° = 180°-105° = 75°
sum of all angles of triangle = 180°
x°+ y°+z° = 180°
x° + 70°+75° = 180°
x° = 180°-145° = 35°
hope this helps
then, angle B = y = 70° ( alternate interior angle)
now ,
angle BCA + angle BCE + angle ECD = 180°
( as ACD is a straight line )
z°+y°+35° = 180°
z° +70°+35° = 180°
z° = 180°-105° = 75°
sum of all angles of triangle = 180°
x°+ y°+z° = 180°
x° + 70°+75° = 180°
x° = 180°-145° = 35°
hope this helps
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