Math, asked by Ammie999, 1 year ago

in the given figure angle b is equal to angle c show that ae is greater than af.​

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Answered by bhagyashreechowdhury
10

Answer:

Let’s consider ∆ EDB,

∠ABC = ∠EDB + ∠BED …. [∵ exterior angles is sum of two non-adjacent interior angles]

⇒ ∠ABC > ∠BED

∵ ∠BED = ∠AEF as they are vertically opposite angles

∠ABC > ∠AEF …….. (i)

Now, let’s consider ∆ FDC,

∠AFE = ∠FDC +∠FCD …. [∵ exterior angles is sum of two non-adjacent interior angles]

⇒ ∠AFE > ∠FCD

∠AFE > ∠ABC ……(ii) [∵ ∠B = ∠C given in the question]

From (i) & (ii), we can write,

∠AFE > ∠AEF

∵ A side opposite to greater angle is always greater and vice-versa.

AE > AF

Hence proved

Answered by govind2909
1

Step-by-step explanation:

I hope this will be helpful for you

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