in the given figure angle b is less than angle a and angle c is less than angle d show that angle ad is less than bc
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Let the point of intersection of BC and AD be O
In △ABO
⇒∠B<∠A
Thereore, ⇒AO<BO (1) (side opposite to greater angle is largest)
Similarly,
In △COD
⇒∠C<∠D
Thereore, ⇒DO<CO (2) (side opposite to greater angle is largest)
Adding (1) and (2) we get,
⇒BO+OC>AO+DO
⇒BC>AD
Hence proved.
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