Question

In the given figure, angle B < angle A and angle C <angle D.
Show that AD <BC.

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Answer 1

Step-by-step explanation:

$\huge{\underline{\mathtt{\red{❥A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$ANSWER

In △AOB,

∠B<∠A

∴AO<BO

∴ Side opposite to the greater angle is longer.

In △COD,

∠C<∠D⇒OD<OC

⇒AO+OD<OB+OC

∴AD<BC