Question

in the given figure,angle B< angle A and angle C< angle D. show that AD< BC

Answer 1

GIVEN
              angle b < angle a
              angle c < angle d
 
TO PROVE
                  
                   AD < BC
PROOF
              angle b < angle a
        SO, 
               OA < OB  ( SIDE OPPOSITE TO SMALLER ANGLE IS SMALL ITS THEOREM GIVEN IN NCERT) LET THE ABOVE ONE BE 1
      
       NOW, 
                  angle c < angle d
          SO, 
               OD <  OC ( SIDE OPPOSITE TO SMALLER ANGLE IS SMALL ITS THEOREM GIVEN IN NCERT)
​  LET THE ABOVE ONE BE 2

NOW, 
             ADDING 1 AND 2
   
      OA + OD < OB + OC
ADDING WE GET,  

       AD < BC
                       HENCE PROVED

Answer 2

Answer:

Step-by-step explanation:

Given: ∠B < ∠A and, ∠C < ∠D

Now,

AO < BO (i) (Side opposite to the smaller angle is smaller)

OD < OC (ii) (Side opposite to the smaller angle is smaller)

Adding (i) and (ii), we get

AO + OD < BO + OC

AD < BC

Hence Proved.