Question

In the given figure Angle BEA is

correct will get follow​

Answer 1

Answer:

the angle BEA is $70^0$

Step-by-step explanation:

Given:

Angle DCB is $60^0$

Angle EAB is $50^0$

We need to find the angle BEA

Since CD is parallel to AB

Angle DCB is equal to Angle ABC

From triangle EAB

The sum of angles in a triangle is $180^0$

Then we get:

$\alpha +50^0+60^0=180^0\\\\\alpha +110^0=180^0\\\\\alpha =70^0$