Question

In the given figure angle BTO=30°. Find angle ATO,where O is the centre of the circle and TA and TB are tangents

Answer 1

Solution :-

In Δ ATO and Δ BTO

OA=OB (Radii of circle)

∠OAT=∠OBT=90°

Line from the center of the circle to the point of contact of tangent is perpendicular to the tangent.

AT=BT

→→Length of tangents from external point to a circle are equal.

Δ ATO ≅ Δ BTO

∠ ATO = ∠ BTO

As, ∠ BTO = 30°

So, ∠ ATO = 30°
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@GauravSaxena01

Answer 2

Answer:

∆ ATO perpendicular ∆BTO

Step-by-step explanation:

∆ATO=∆BTO. As, ∆BTO=30°. so, ∆ATO=30°