in the given figure, angle X=62 degree , angle XYZ = 54q degree . In ∆XYZ. If YO and ZO are bisectors of angle XYZ and angle XZY respectively find angle OZY and angle YOZ
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Lines and Angles
In figure, ∠X = 62°, ∠XYZ = 54°. If YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively of ∆XYZ, find ∠OZY and ∠YOZ. ⇒ ∠YOZ = 180° - 59° = 121°.
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In trinagle XYZ ,
angle X = 62 degree and angle Y= 54 degree
sum of angles of triangle is 180 degree ,
therefore , angle ( X + Y + Z ) = 180 degree
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