Question

In the given figure, angleA = 90° and AD perpendicularto BC . Prove
that angleBAD = angleACB.
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Answer 1

Answer:

Step-by-step explanation:

using angle sum property,

∠ BAC= ∠BAD + ∠DAC = 90°    ---- eq-1

AND     ∠BCA + ∠DAC = 90°    ---- eq-2    

                                                                  ∵ ∠DCA + ∠DAC +∠CDA = 180°

From equation 1 and 2,

∠BAD + ∠DAC =  ∠ACB + ∠DAC

⇒ ∠BAD = ∠ACB

    Hence proved.