Math, asked by MR2018, 1 year ago

In the given figure, angleABC =65°,angleBCE =30°,angleDCE =35°and angle CEF =145°.show that AB||EF

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Answered by Gauravbhatt98
161
Angle AB = 65{ GIVEN }
Angle BCD = Angle BCE + ECD = 30 + 35 = 65.
They are alternate angles
So, AB parallel CD ----------(1)
=> Angle ECD + Angle CEF = 180
=> Angle ECD & Angle CEF are Co-interior
=> EF parallel to CD -------------(2)
=> From (1) & (2)
=> AB parallel to CD & CD parallel EF
=> CD will be cancelled
=> AB parallel to EF
HENCE PROVED
Answered by appadudora
73

Answer:Angle AB = 65{ GIVEN }

Step-by-step explanation:

Angle BCD = Angle BCE + ECD = 30 + 35 = 65.

They are alternate angles

So, AB parallel CD ----------(1)

=> Angle ECD + Angle CEF = 180

=> Angle ECD & Angle CEF are Co-interior

=> EF parallel to CD -------------(2)

=> From (1) & (2)

=> AB parallel to CD & CD parallel EF

=> CD will be cancelled

=> AB parallel to EF

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