In the given figure, angleABC =65°,angleBCE =30°,angleDCE =35°and angle CEF =145°.show that AB||EF
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161
Angle AB = 65{ GIVEN }
Angle BCD = Angle BCE + ECD = 30 + 35 = 65.
They are alternate angles
So, AB parallel CD ----------(1)
=> Angle ECD + Angle CEF = 180
=> Angle ECD & Angle CEF are Co-interior
=> EF parallel to CD -------------(2)
=> From (1) & (2)
=> AB parallel to CD & CD parallel EF
=> CD will be cancelled
=> AB parallel to EF
HENCE PROVED
Angle BCD = Angle BCE + ECD = 30 + 35 = 65.
They are alternate angles
So, AB parallel CD ----------(1)
=> Angle ECD + Angle CEF = 180
=> Angle ECD & Angle CEF are Co-interior
=> EF parallel to CD -------------(2)
=> From (1) & (2)
=> AB parallel to CD & CD parallel EF
=> CD will be cancelled
=> AB parallel to EF
HENCE PROVED
Answered by
73
Answer:Angle AB = 65{ GIVEN }
Step-by-step explanation:
Angle BCD = Angle BCE + ECD = 30 + 35 = 65.
They are alternate angles
So, AB parallel CD ----------(1)
=> Angle ECD + Angle CEF = 180
=> Angle ECD & Angle CEF are Co-interior
=> EF parallel to CD -------------(2)
=> From (1) & (2)
=> AB parallel to CD & CD parallel EF
=> CD will be cancelled
=> AB parallel to EF
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