Question

In the given figure, angleABC is inscribed in a circle. If
the bisector of angleBAC meets BC at D and the circle
at E such that angleECD = 30°, then angleBAC is
А
30°
D
B
С
E
(1) 30°
(3) 50°
(2) 40°
(4) 60°
PLEASE ANSWER. PLEASEEE​

Answer 1

may it's helpful to you.