Question

In the given figure, angleADB = angleACB and angleABD = angleBAC. Prove that AD = BC. ​

Answer 1

Answer:

→Angle ADB-Angle ACB(Given) →Angle ABD=Angle BAC(Given) →BA=BA(common)

HENCE,

→AABD=ABAC=(AAS)

and AD=BC (From AABD=ABAC) Hence proved

Step-by-step explanation:

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