Question

In the given figure, anglePAB=60° and angleCAB=30° and PB=75. Find BC

Answer 1

IN ΔPBA

tan60°=75/AB

AB√3=75

AB= 75/√3

NOW IN ΔCBA

tan30°=BC/AB

1/√3=BC/ AB

1/√3= √3 BC/ 75

75=3BC

BC=75/3 m