In the given figure, anglePAB=60° and angleCAB=30° and PB=75. Find BC
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IN ΔPBA
tan60°=75/AB
AB√3=75
AB= 75/√3
NOW IN ΔCBA
tan30°=BC/AB
1/√3=BC/ AB
1/√3= √3 BC/ 75
75=3BC
BC=75/3 m
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