In the given figure AO ⊥ OB,OC is bisector find the value of ∠AOC and ∠BOC
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Answer:
Step-by-stAO PERPENDICULAR TO OB
BOTH THE ANGLES SHOULD BE EQUAL
FIRST FIND X
(2X-5) + (X-10)=90
2X-5+X-10=90
3X - 15 = 90
3X = 90 - 15
3X = 75
X = 75/3
X = 25
THEREFORE X = 25
AOC = 2X - 5
= 2*25 - 5
= 50 - 5
= 45
OTHER SHOULD BE 45 ONLY AS AOB IS 90 AS 45*2=90ep explanation:
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