Question

In the given figure AOB ia straight line, Find i) the value of x ii) ∠ iii) ∠ iii) ∠.​

Answer 1

(x-10°) + (4x-25°) + (x+5°) = 180° (Angle on a straight line is 180°)

6x-30° = 180°

6x = 180° + 30°

6x = 210°

x = 210°/6

x = 35°

Angle AOD = 35°-10° = 25°

Angle DOC = 4(35°) - 25° = 140° - 25°

= 115°

Angle BOC = 35°+5° = 40°

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