Question

In the given figure , AOB is a straight line and the ray OC stands on it.
If angle AOB = (2x - 10)° and
angle BOC = (3x + 20)° , find the value of X and also find the angles AOB and BOC​

Answer 1

Step-by-step explanation:

its a straight line so it will be equal to 180°

(2x-10)°+(3x+20)°=180°

2x+3x-10+20=180°

5x+10=180°

5x =180-10

5x = 170

x = 170/5

x = 34°

Hope it helps you..!!!!!

Answer 2

Step-by-step explanation:

we know that angle on a straight line is 180 degree.

AOB +BOC = 180

2x-10 +3x+20= 180

5x= 180-10

5x=170

x= 34

AOB = 2x-10

= 2*34 -10

=68 -10

= 58

BOC = 3x+20

= 3*34+20

=102+20

=122