Question

In the given figure, AOB is a straight line and the ray OC stands on it. If ∠AOC = (2x - 25)° and ∠BOC = (3x+5)°, find the value of x. Also find ∠AOC and ∠BOC. ​

Answer 1

Answer:

we know

sum of angel on line=180°

2x-25+3x+5=180

5x-20=180

5x=200

x= 40

angel of AOC=(2x-25)

= (2×40-25)

= (80-25) = ( 55°)

angel of BOC =(3x+5)

= (3×40+5) = ( 120+5) = (125)

Answer 2

Answer:

angle AOC +angle BOC= 180° (linear pair)

(2x-25)+(3x+5)=180

2x-25+3x+5=180

5x-20=180

5x=180+20

5x=200

x=40

angle AOC=2x-25

=2(40)-25

=80-25

angle AOC=55°

angle BOC=3x+5

=3(40)+5

=120+5

angle BOC=125°

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