in the given figure Aob is a straight line and the ray OC and of stand on it. <Aoc.=65 <Bod=70 <cod =x find the value
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Given
AOB is a straight line
Then ∠AOB = 180°
Ray OC & Ray OD stands on line AOB
∠AOC = 65°
∠BOD = 70°
TO FIND
∠COD = x°
Here,
∠AOB = ∠AOC + ∠COD + ∠BOD
180° = 65° + 70° + x°
180° - 135° = x°
x° = 55°
Note: straight line = 180°
Because it has two right angles if we divide perpendicularly
And we know that right angle = 90°
2 right angles = 2(90°) = 180°
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