Question

in the given figure AOB is a straight line and the ray OC stands on it. If ZAOC = (4x) and/BOC = (x+10), find the value of x. Also find AOC and Z BOC.​

Answer 1

Given:

∠AOC = 4x

∠BOC = (x+10)

As we know, AOC and BOC are a linear pair, so

∠AOC + ∠BOC = 180*

Substituting with the given values:

4x + x + 10 = 180*

5x + 10 = 180*

5x = 180*-10*

5x = 170*

x = 170*/5

x = 34*

Knowing this, we can solve for ∠AOC and ∠BOC

∠AOC = 4x = 4*34 = 136

∠BOC = x + 10 = 34 + 10 = 44

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Answer 2

Answer:

aoc+cob = 180

4x + x+10 =180

5x+10=180

5x = 180-10

x = 170/5

x =34

aoc = 4x = 136

boc = x+10 = 44