Question

in the given figure ,AOB is a straight line and the ray OC stands on it

If angle AOC =(2x-10°) and angle BOC= (3x+20°),find the value of x.

Answer 1

The figure will be as shown,
Given, angle AOC = (2x - 10°) and angle BOC = (3x + 20°) also, AOB is a straight line.
The sum of two angles on a straight line is 180° .
As, AOB is a straight line ;
=> angle AOC + angle BOC = 180°
=> (2x-10) + (3x+20) = 180
=> 2x - 10 + 3x + 20 = 180
=> 5x + 10 = 180
=> 5x = 180 - 10
=> 5x = 170
=> x = 170/5
=> x = 34 Answer.

Answer 2

Concept Introduction:-

A straight line are the one-dimensional shape with no width that never ends.

Given Information:-

We have been given that angle $AOC =(2x-10^{\circ})$ and angle $BOC= (3x+20^{\circ})$.

To Find:-

We have to find that the value of $x$.

Solution:-

According to the problem

The sum of two angles on a straight line is $180^{\circ}$.

As $AOB$ is a straight line;

$\Rightarrow\ angle \mathrm{AOC}+ angle \mathrm{B} \mathrm{OC}=180^{\circ}\\\Rightarrow(2 x-10)+(3 x+20)=180\\\Rightarrow 2 x-10+3 x+20=180\\\Rightarrow 5 x+10=180\\\Rightarrow 5 x=180-10\\\Rightarrow 5 x=170\\\Rightarrow x=170 / 5\\\Rightarrow x=34$

Final Answer:-

The value of $x$ is $34$.

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