In the given figure, AOB is a straight line. Find the measure of 3a + b aod=a+2b doc=90 cob=2a-b
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Answer:
OD is bisector of AOC
therefore, angle AOD = DOC
and similarly
OE is bisector of BOC
therefore,angle COE = EOB
Now
let,
angle AOD = A , DOC = B , COE = C and EOB = D
and, A = B and C = D ( because OD and OE are angle bisectors)
therefore,
we know that,sum of all interior angles is 180°
So,
AOD + DOC + COE + EOB = 180°
A + B + C + D = 180°
A + A + B + B = 180°
2A + 2B = 180°
2 ( A+B ) = 180°
A + B = 180° / 2
A + B = 90°
DOC + COE = 90°
DOE = 90°
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idk bro. sorry!
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