Question

In the given figure , AOB is a straight line. If /_ AOC = (3x - 10)° and /_ BOC = (4x-26)° , then
/_ BOC = ?


Please explain me .​

Answer 1

Question:

In the given figure , AOB is a straight line. If ∠AOC = (3x - 10)° and ∠BOC = (4x-26)° , then ∠BOC = ?

Given:

1. AOB is a straight line.
2. ∠AOC = (3x - 10)°
3. ∠BOC = (4x - 26)°

To Find:

• ∠BOC = ?

Answer:

∠BOC = 86°.

Solution:

If AOB is a straight angle.

➺ $(3x - 10)° + (4x - 26)° = 180°${Straight Angle}

➺ $7x - 16 = 180°$

➺ $7x = 180 + 16$

➺ $7x = 196°$

➺ $x = \frac{\cancel 196}{\cancel 7}$

➺ $\huge \boxed {x = 28}$

So,

∠BOC = (4x - 26)°

➺ (4(28) - 26)°

➺ (112 - 26)°

➺ 86°

$\huge \boxed{∠BOC = 86°}$

Answer 2

Step-by-step explanation:

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