In the given figure , AOB is a straight line. If /_ AOC =(3x+10)° and /_ BOC = (4x-26)° , then
/_ BOC = ?
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AOC + BOC=180°......( angles in linear pair)
(3x+10) + (4x-26) =180°
3x+10+4x-26=180°
7x-16=180
7x=180+16
7x=196
x=196/7
x=28
BOC=4x-26
=4×28-26
=112-26
=86°
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