Math, asked by krishnaswamy80, 8 months ago

In the given figure, AP and AQ are two tangents drawn to the circle with centre O. B is a point on the extended tangent OA and ∠PAB = 135°. Find ∠POQ
B

Attachments:

Answers

Answered by filus139
4

Step-by-step explanation:

Lqac=135°

Lpaq+ Lpab=180°

Lpaq+135°=180°

Lpaq=180°-135°

Lpaq=45°

Lpoq+Lpaq=180°

Lpoq+45°=180°

Lpoq=180°-45°

Lpoq=135°

Similar questions