Question

In the given figure, AP, AQ, BP and BQ are angle bisector of interior angles, find angle QBA and angle ABP​

Answer 1

Given :  In the given figure, AP, AQ, BP and BQ are angle bisector of interior angles,

To find : angle QBA and angle ABP​

Solution:

∠ABP = 40°  as BP is angle bisector

=> 40 ° + 40 ° = 80°

Angle on other side = 180° - 80° = 100°

BQ is angle bisector

=> ∠QBA = 100°/2 = 50°

=> ∠QBA =  50°

∠ABP = 40°  

∠QBA =  50°

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